Let $x = x ( t )$ and $y = y ( t )$ be solutions of the differential equations $\frac { \mathrm { dx } } { \mathrm { dt } } + \mathrm { ax } = 0$ and $\frac { \mathrm { dy } } { \mathrm { dt } } + $ by $= 0$ respectively, $\mathrm { a } , \mathrm { b } \in \mathrm { R }$. Given that $x ( 0 ) = 2 ; y ( 0 ) = 1$ and $3 y ( 1 ) = 2 x ( 1 )$, the value of $t$, for which $x ( t ) = y ( t )$, is:\\
(1) $\log _ { \frac { 2 } { 3 } } 2$\\
(2) $\log _ { 4 } 3$\\
(3) $\log _ { 3 } 4$\\
(4) $\log _ { \frac { 4 } { 3 } } 2$