When the numbers $2,3,4,5,6,7,8$ and 9 are placed in the boxes below such that each box contains a different number, all equalities are satisfied.
$$\begin{aligned}
& \square \times \square = 12 \\
& A \div \square = 2 \\
& \square + \square = 12 \\
& B - \square = 2
\end{aligned}$$
Accordingly, what is the sum $A + B$?
A) 13
B) 14
C) 15
D) 16
E) 17