An equilateral triangle with red-colored sides and an equilateral triangle with blue-colored sides are drawn such that one vertex of each is on a side of the other triangle, as shown in the figure. In the resulting figure, the area of the yellow-colored triangle equals 4 times the area of the gray-colored triangle. Accordingly, what is the ratio of the area of the triangle with red-colored sides to the area of the triangle with blue-colored sides? A) $\frac{2}{3}$ B) $\frac{5}{6}$ C) $\frac{8}{9}$ D) $\frac{25}{27}$ E) $\frac{25}{36}$
An equilateral triangle with red-colored sides and an equilateral triangle with blue-colored sides are drawn such that one vertex of each is on a side of the other triangle, as shown in the figure.
In the resulting figure, the area of the yellow-colored triangle equals 4 times the area of the gray-colored triangle.
Accordingly, what is the ratio of the area of the triangle with red-colored sides to the area of the triangle with blue-colored sides?
A) $\frac{2}{3}$
B) $\frac{5}{6}$
C) $\frac{8}{9}$
D) $\frac{25}{27}$
E) $\frac{25}{36}$