For two conditions on real number $x$:
$$\begin{aligned}
& p : ( x - 1 ) ( x - 4 ) = 0 , \\
& q : 1 < 2 x \leq a
\end{aligned}$$
Find the minimum value of the natural number $a$ such that $p$ is a sufficient condition for $q$. [3 points]\\
(1) 4\\
(2) 5\\
(3) 6\\
(4) 7\\
(5) 8