The probability distribution of the random variable $X$ is shown in the table below.
\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\hline
$X$ & 0.121 & 0.221 & 0.321 & Total \\
\hline
$\mathrm { P } ( X = x )$ & $a$ & $b$ & $\frac { 2 } { 3 }$ & 1 \\
\hline
\end{tabular}
\end{center}
The following is the process of finding $\mathrm { V } ( X )$ when $\mathrm { E } ( X ) = 0.271$.\\
Let $Y = 10 X - 2.21$. The probability distribution of the random variable $Y$ is shown in the table below.
\begin{center}
\begin{tabular}{ | c | c | c | c | c | }
\hline
$Y$ & $-1$ & 0 & 1 & Total \\
\hline
$\mathrm { P } ( Y = y )$ & $a$ & $b$ & $\frac { 2 } { 3 }$ & 1 \\
\hline
\end{tabular}
\end{center}
Since $\mathrm { E } ( Y ) = 10 \mathrm { E } ( X ) - 2.21 = 0.5$,\\
$a =$ (가), $b =$ (나)\\
and $\mathrm { V } ( Y ) = \frac { 7 } { 12 }$.\\
On the other hand, since $Y = 10 X - 2.21$, we have $\mathrm { V } ( Y ) =$ (다) $\times \mathrm { V } ( X )$. Therefore, $\mathrm { V } ( X ) = \frac { 1 } { \text{(다)} } \times \frac { 7 } { 12 }$.\\
When the values in (가), (나), and (다) are $p$, $q$, and $r$ respectively, find the value of $pqr$. (Here, $a$ and $b$ are constants.) [4 points]\\
(1) $\frac { 13 } { 9 }$\\
(2) $\frac { 16 } { 9 }$\\
(3) $\frac { 19 } { 9 }$\\
(4) $\frac { 22 } { 9 }$\\
(5) $\frac { 25 } { 9 }$