Consider a triangle $ABC$. The sides $AB$ and $AC$ are extended to points $D$ and $E$, respectively, such that $AD = 3AB$ and $AE = 3AC$. Then one diagonal of $BDEC$ divides the other diagonal in the ratio\\
(A) $1 : 3$\\
(B) $1 : \sqrt{3}$\\
(C) $1 : 2$\\
(D) $1 : \sqrt{2}$.