A unit square has its corners chopped off to form a regular polygon with eight sides. What is the area of this polygon? (A) $2(\sqrt{3} - \sqrt{2})$ (B) $2\sqrt{2} - 2$ (C) $\frac{\sqrt{2}}{2}$ (D) $\frac{7}{9}$.
A unit square has its corners chopped off to form a regular polygon with eight sides. What is the area of this polygon?\\
(A) $2(\sqrt{3} - \sqrt{2})$\\
(B) $2\sqrt{2} - 2$\\
(C) $\frac{\sqrt{2}}{2}$\\
(D) $\frac{7}{9}$.