Consider all the permutations of the twenty six English letters that start with $z$. In how many of these permutations the number of letters between $z$ and $y$ is less than those between $y$ and $x$?\\
(A) $6 \times 23!$\\
(B) $6 \times 24!$\\
(C) $156 \times 23!$\\
(D) $156 \times 24!$.