Total number of 6-digit numbers in which only and all the five digits $1, 3, 5, 7$ and 9 appears, is (1) $\frac { 1 } { 2 } (6!)$ (2) $6!$ (3) $5 ^ { 6 }$ (4) $\frac { 5 } { 2 } (6!)$
Total number of 6-digit numbers in which only and all the five digits $1, 3, 5, 7$ and 9 appears, is\\
(1) $\frac { 1 } { 2 } (6!)$\\
(2) $6!$\\
(3) $5 ^ { 6 }$\\
(4) $\frac { 5 } { 2 } (6!)$