jee-main 2020 Q67

jee-main · India · session1_07jan_shift1 Differential equations Solving Separable DEs with Initial Conditions

If $y = y(x)$ is the solution of the differential equation, $e ^ { y } \left( \frac { d y } { d x } - 1 \right) = e ^ { x }$ such that $y(0) = 0$, then $y(1)$ is equal to
(1) $1 + \log _ { e } 2$
(2) $2 + \log _ { e } 2$
(3) $2e$
(4) $\log _ { e } 2$

If $y = y(x)$ is the solution of the differential equation, $e ^ { y } \left( \frac { d y } { d x } - 1 \right) = e ^ { x }$ such that $y(0) = 0$, then $y(1)$ is equal to\\
(1) $1 + \log _ { e } 2$\\
(2) $2 + \log _ { e } 2$\\
(3) $2e$\\
(4) $\log _ { e } 2$

Paper Questions

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