jee-main 2021 Q72

jee-main · India · session2_17mar_shift1 Matrices Linear System and Inverse Existence
The system of equations $kx + y + z = 1$, $x + ky + z = k$ and $x + y + zk = k^2$ has no solution if $k$ is equal to:
(1) 0
(2) 1
(3) $-1$
(4) $-2$
The system of equations $kx + y + z = 1$, $x + ky + z = k$ and $x + y + zk = k^2$ has no solution if $k$ is equal to:\\
(1) 0\\
(2) 1\\
(3) $-1$\\
(4) $-2$