jee-main 2023 Q66

jee-main · India · session1_24jan_shift1 Proof Proof of Equivalence or Logical Relationship Between Conditions

The compound statement $( \sim ( P \wedge Q ) ) \vee ( ( \sim P ) \wedge Q ) \Rightarrow ( ( \sim P ) \wedge ( \sim Q ) )$ is equivalent to
(1) $( ( \sim P ) \vee Q ) \wedge ( ( \sim Q ) \vee P )$
(2) $( \sim Q ) \vee P$
(3) $( ( \sim P ) \vee Q ) \wedge ( \sim Q )$
(4) $( \sim P ) \vee Q$

The compound statement $( \sim ( P \wedge Q ) ) \vee ( ( \sim P ) \wedge Q ) \Rightarrow ( ( \sim P ) \wedge ( \sim Q ) )$ is equivalent to\\
(1) $( ( \sim P ) \vee Q ) \wedge ( ( \sim Q ) \vee P )$\\
(2) $( \sim Q ) \vee P$\\
(3) $( ( \sim P ) \vee Q ) \wedge ( \sim Q )$\\
(4) $( \sim P ) \vee Q$

Paper Questions

Q21 Q61 Q62 Q63 Q64 Q65 Q66 Q67 Q68 Q69 Q70 Q71 Q72