Let $p$ and $q$ be two statements. Then $\sim ( p \wedge ( p \rightarrow \sim q ) )$ is equivalent to (1) $p \vee ( p \wedge ( \sim q ) )$ (2) $p \vee ( ( \sim p ) \wedge q )$ (3) $( \sim p ) \vee q$ (4) $p \wedge q$
Let $p$ and $q$ be two statements. Then $\sim ( p \wedge ( p \rightarrow \sim q ) )$ is equivalent to\\
(1) $p \vee ( p \wedge ( \sim q ) )$\\
(2) $p \vee ( ( \sim p ) \wedge q )$\\
(3) $( \sim p ) \vee q$\\
(4) $p \wedge q$