In a triangle $ABC$, the circumradius is $r$ and $BC = r/2$. The circumcentre $O$ lies on $AD$ where $D$ is the midpoint of $BC$. Find the ratio $BC : AD$.
(A) $\sqrt{3} : \sqrt{2}$ (B) $\sqrt{2} : \sqrt{3}$ (C) $1 : \sqrt{3}$ (D) $\sqrt{3} : 1$
(A) $BC : AD = \sqrt{3} : \sqrt{2}$
In a triangle $ABC$, the circumradius is $r$ and $BC = r/2$. The circumcentre $O$ lies on $AD$ where $D$ is the midpoint of $BC$. Find the ratio $BC : AD$.

(A) $\sqrt{3} : \sqrt{2}$ \quad (B) $\sqrt{2} : \sqrt{3}$ \quad (C) $1 : \sqrt{3}$ \quad (D) $\sqrt{3} : 1$