$f : [ 1 , \infty ) \rightarrow [ 1 , \infty )$ is a function and $$f \left( e ^ { x } \right) = \sqrt { x } + 1$$ Given this, what is the value of $f ^ { - 1 } ( 2 )$? A) 1 B) $e - 1$ C) e D) $e ^ { 2 }$ E) $\ln 2$
$f : [ 1 , \infty ) \rightarrow [ 1 , \infty )$ is a function and
$$f \left( e ^ { x } \right) = \sqrt { x } + 1$$
Given this, what is the value of $f ^ { - 1 } ( 2 )$?\\
A) 1\\
B) $e - 1$\\
C) e\\
D) $e ^ { 2 }$\\
E) $\ln 2$