jee-advanced 2012 Q38

jee-advanced · India · paper1 Not Maths
38. When the following aldohexose exists in its D-configuration, the total number of stereoisomers in its pyranose form is [Figure]
ANSWER : 8
  1. $29.2 \% ( \mathrm { w } / \mathrm { w } ) \mathrm { HCl }$ stock solution has a density of $1.25 \mathrm {~g} \mathrm {~mL} ^ { - 1 }$. The molecular weight of HCl is $36.5 \mathrm {~g} \mathrm {~mol} ^ { - 1 }$. The volume $( \mathrm { mL } )$ of stock solution required to prepare a 200 mL solution of 0.4 M HCl is

ANSWER : 8
  1. An organic compound undergoes first-order decomposition. The time taken for its decomposition to $1 / 8$ and $1 / 10$ of its initial concentration are $t _ { 1 / 8 }$ and $t _ { 1 / 10 }$ respectively. What is the value of $\frac { \left[ \mathrm { t } _ { 1 / 8 } \right] } { \left[ \mathrm { t } _ { 1 / 10 } \right] } \times 10 ? \quad \left( \right.$ take $\left. \log _ { 10 } 2 = 0.3 \right)$

ANSWER : 9
PART III : MATHEMATICS
SECTION I : Single Correct Answer Type
This section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.
An organic compound undergoes first-order decomposition. The time taken for its decomposition to $1 / 8$ and $1 / 10$ of its initial concentration are $t _ { 1 / 8 }$ and $t _ { 1 / 10 }$ respectively. What is the value of $\frac { \left[ t _ { 1 / 8 } \right] } { \left[ t _ { 1 / 10 } \right] } \times 10$ ? (take $\log _ { 10 } 2 =$ 0.3)
38. When the following aldohexose exists in its D-configuration, the total number of stereoisomers in its pyranose form is\\
\includegraphics[alt={}]{smile-3770825e7813f5ba17e22367901e70004719f98f}

\section*{ANSWER : 8}
\begin{enumerate}
  \setcounter{enumi}{38}
  \item $29.2 \% ( \mathrm { w } / \mathrm { w } ) \mathrm { HCl }$ stock solution has a density of $1.25 \mathrm {~g} \mathrm {~mL} ^ { - 1 }$. The molecular weight of HCl is $36.5 \mathrm {~g} \mathrm {~mol} ^ { - 1 }$. The volume $( \mathrm { mL } )$ of stock solution required to prepare a 200 mL solution of 0.4 M HCl is
\end{enumerate}

\section*{ANSWER : 8}
\begin{enumerate}
  \setcounter{enumi}{39}
  \item An organic compound undergoes first-order decomposition. The time taken for its decomposition to $1 / 8$ and $1 / 10$ of its initial concentration are $t _ { 1 / 8 }$ and $t _ { 1 / 10 }$ respectively. What is the value of $\frac { \left[ \mathrm { t } _ { 1 / 8 } \right] } { \left[ \mathrm { t } _ { 1 / 10 } \right] } \times 10 ? \quad \left( \right.$ take $\left. \log _ { 10 } 2 = 0.3 \right)$
\end{enumerate}

\section*{ANSWER : 9}
\section*{PART III : MATHEMATICS}
\section*{SECTION I : Single Correct Answer Type}
This section contains 10 multiple choice questions. Each question has four choices (A), (B), (C) and (D) out of which ONLY ONE is correct.\\