If a line $L$ is perpendicular to the line $5 x - y = 1$, and the area of the triangle formed by the line $L$ and the coordinate axes is 5 sq units, then the distance of the line $L$ from the line $x + 5 y = 0$ is\\
(1) $\frac { 7 } { \sqrt { 13 } }$ units\\
(2) $\frac { 7 } { \sqrt { 5 } }$ units\\
(3) $\frac { 5 } { \sqrt { 13 } }$ units\\
(4) $\frac { 5 } { \sqrt { 7 } }$ units