jee-main 2014 Q69

jee-main · India · 19apr Circles Circle Equation Derivation
The equation of the circle described on the chord $3 x + y + 5 = 0$ of the circle $x ^ { 2 } + y ^ { 2 } = 16$ as the diameter is
(1) $x ^ { 2 } + y ^ { 2 } + 3 x + y + 1 = 0$
(2) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 22 = 0$
(3) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 11 = 0$
(4) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 2 = 0$
The equation of the circle described on the chord $3 x + y + 5 = 0$ of the circle $x ^ { 2 } + y ^ { 2 } = 16$ as the diameter is\\
(1) $x ^ { 2 } + y ^ { 2 } + 3 x + y + 1 = 0$\\
(2) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 22 = 0$\\
(3) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 11 = 0$\\
(4) $x ^ { 2 } + y ^ { 2 } + 3 x + y - 2 = 0$