jee-main 2014 Q81

jee-main · India · 19apr Applied differentiation Applied modeling with differentiation

If the volume of a spherical ball is increasing at the rate of $4 \pi \mathrm { cc } / \mathrm { sec }$ then the rate of increase of its radius (in $\mathrm { cm } / \mathrm { sec }$), when the volume is $288 \pi \mathrm { cc }$ is
(1) $\frac { 1 } { 9 }$
(2) $\frac { 1 } { 6 }$
(3) $\frac { 1 } { 24 }$
(4) $\frac { 1 } { 36 }$

If the volume of a spherical ball is increasing at the rate of $4 \pi \mathrm { cc } / \mathrm { sec }$ then the rate of increase of its radius (in $\mathrm { cm } / \mathrm { sec }$), when the volume is $288 \pi \mathrm { cc }$ is\\
(1) $\frac { 1 } { 9 }$\\
(2) $\frac { 1 } { 6 }$\\
(3) $\frac { 1 } { 24 }$\\
(4) $\frac { 1 } { 36 }$

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