jee-main 2019 Q61

jee-main · India · session2_08apr_shift1 Solving quadratics and applications Solving an equation via substitution to reduce to quadratic form

The sum of the solutions of the equation $\sqrt{x} - 2 + \sqrt{x}\sqrt{x} - 4 + 2 = 0, x > 0$ is equal to
(1) 10
(2) 9
(3) 12
(4) 4

The sum of the solutions of the equation $\sqrt{x} - 2 + \sqrt{x}\sqrt{x} - 4 + 2 = 0, x > 0$ is equal to\\
(1) 10\\
(2) 9\\
(3) 12\\
(4) 4