jee-main 2019 Q62

jee-main · India · session2_08apr_shift1 Roots of polynomials Vieta's formulas: compute symmetric functions of roots
If $\alpha$ and $\beta$ be the roots of the equation $x^2 - 2x + 2 = 0$, then the least value of $n$ for which $\frac{\alpha^n}{\beta} = 1$ is
(1) 5
(2) 4
(3) 2
(4) 3
If $\alpha$ and $\beta$ be the roots of the equation $x^2 - 2x + 2 = 0$, then the least value of $n$ for which $\frac{\alpha^n}{\beta} = 1$ is\\
(1) 5\\
(2) 4\\
(3) 2\\
(4) 3