If $f(x) = \log_e\frac{1-x}{1+x}$, $|x| < 1$, then $f\left(\frac{2x}{1+x^2}\right)$ is equal to\\ (1) $f(x^2)$\\ (2) $2f(x^2)$\\ (3) $-2f(x)$\\ (4) $2f(x)$