If $f(x) = \frac{2 - x\cos x}{2 + x\cos x}$ and $g(x) = \log_e x$, then the value of the integral $\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} g(f(x))\, dx$ is (1) $\log_e e$ (2) $\log_e 2$ (3) $\log_e 1$ (4) $\log_e 3$
If $f(x) = \frac{2 - x\cos x}{2 + x\cos x}$ and $g(x) = \log_e x$, then the value of the integral $\int_{-\frac{\pi}{4}}^{\frac{\pi}{4}} g(f(x))\, dx$ is\\
(1) $\log_e e$\\
(2) $\log_e 2$\\
(3) $\log_e 1$\\
(4) $\log_e 3$