If $\alpha = \cos^{-1}\frac{3}{5}$, $\beta = \tan^{-1}\frac{1}{3}$, where $0 < \alpha, \beta < \frac{\pi}{2}$, then $\alpha - \beta$ is equal to\\
(1) $\tan^{-1}\frac{9}{14}$\\
(2) $\cos^{-1}\frac{9}{5\sqrt{10}}$\\
(3) $\sin^{-1}\frac{9}{5\sqrt{10}}$\\
(4) $\tan^{-1}\frac{9}{5\sqrt{10}}$