jee-main 2022 Q66

jee-main · India · session2_25jul_shift1 Sequences and series, recurrence and convergence Convergence proof and limit determination
If $\lim _ { n \rightarrow \infty } \left( \sqrt { n ^ { 2 } - n - 1 } + n\alpha + \beta \right) = 0$ then $8\alpha + \beta$ is equal to
(1) 4
(2) - 8
(3) - 4
(4) 8 
If $\lim _ { n \rightarrow \infty } \left( \sqrt { n ^ { 2 } - n - 1 } + n\alpha + \beta \right) = 0$ then $8\alpha + \beta$ is equal to\\
(1) 4\\
(2) - 8\\
(3) - 4\\
(4) 8
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