If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is:\\
(1) $\frac { 33 } { 2 ^ { 32 } }$\\
(2) $\frac { 33 } { 2 ^ { 29 } }$\\
(3) $\frac { 33 } { 2 ^ { 28 } }$\\
(4) $\frac { 33 } { 2 ^ { 27 } }$