If the numbers appeared on the two throws of a fair six faced die are $\alpha$ and $\beta$, then the probability that $x ^ { 2 } + \alpha x + \beta > 0$, for all $x \in R$, is\\
(1) $\frac { 17 } { 36 }$\\
(2) $\frac { 4 } { 9 }$\\
(3) $\frac { 1 } { 2 }$\\
(4) $\frac { 19 } { 36 }$