The lines $\frac { x - 2 } { 2 } = \frac { y } { - 2 } = \frac { z - 7 } { 16 }$ and $\frac { x + 3 } { 4 } = \frac { y + 2 } { 3 } = \frac { z + 2 } { 1 }$ intersect at the point $P$. If the distance of $P$ from the line $\frac { \mathrm { x } + 1 } { 2 } = \frac { \mathrm { y } - 1 } { 3 } = \frac { \mathrm { z } - 1 } { 1 }$ is $l$, then $14 l ^ { 2 }$ is equal to $\_\_\_\_$ .