180- In a uniform electric field $E = 10^5\ \frac{\text{N}}{\text{C}}$, a particle with electric charge $q = -5\ \mu\text{C}$ moves along path $ABC$ from $A$ to $C$. How does the electric potential energy of the particle change along this path? $$\left(\sin\alpha = 0.8\ ,\ AB = BC = 5\ \text{cm}\right)$$ [Figure: Uniform electric field $\vec{E}$ pointing to the right, with path ABC where A is on the left, B is in the middle, and C is at the bottom right, with angle $\alpha$ at B.] \begin{flushright} (1) $0.1$ joule, increases (2) $0.1$ joule, decreases (3) $0.4$ joule, increases (4) $0.4$ joule, decreases \end{flushright} Calculation Space %% Page 17 Physics $\leftarrow$ 122-A $\rightarrow$ Page 8A
\textbf{180-} In a uniform electric field $E = 10^5\ \frac{\text{N}}{\text{C}}$, a particle with electric charge $q = -5\ \mu\text{C}$ moves along path $ABC$ from $A$ to $C$. How does the electric potential energy of the particle change along this path?
$$\left(\sin\alpha = 0.8\ ,\ AB = BC = 5\ \text{cm}\right)$$
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\textit{[Figure: Uniform electric field $\vec{E}$ pointing to the right, with path ABC where A is on the left, B is in the middle, and C is at the bottom right, with angle $\alpha$ at B.]}
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(1) $0.1$ joule, increases\\
(2) $0.1$ joule, decreases\\
(3) $0.4$ joule, increases\\
(4) $0.4$ joule, decreases
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\textbf{Calculation Space}
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\textbf{Physics} \hfill $\leftarrow$ 122-A $\rightarrow$ \hfill \textbf{Page 8A}
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