jee-main 2025 Q75

jee-main · India · session2_08apr_shift1 Differential equations Solving Separable DEs with Initial Conditions

Q75. The solution curve, of the differential equation $2 y \frac { \mathrm {~d} y } { \mathrm {~d} x } + 3 = 5 \frac { \mathrm {~d} y } { \mathrm {~d} x }$, passing through the point $( 0,1 )$ is a conic, whose vertex lies on the line:
(1) $2 x + 3 y = 9$
(2) $2 x + 3 y = - 9$
(3) $2 x + 3 y = - 6$
(4) $2 x + 3 y = 6$

Q75. The solution curve, of the differential equation $2 y \frac { \mathrm {~d} y } { \mathrm {~d} x } + 3 = 5 \frac { \mathrm {~d} y } { \mathrm {~d} x }$, passing through the point $( 0,1 )$ is a conic, whose vertex lies on the line:\\
(1) $2 x + 3 y = 9$\\
(2) $2 x + 3 y = - 9$\\
(3) $2 x + 3 y = - 6$\\
(4) $2 x + 3 y = 6$

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