Q31. Compare the energies of following sets of quantum numbers for multielectron system. (A) $\mathrm { n } = 4,1 = 1$ (B) $\mathrm { n } = 4 , \mathrm { l } = 2 ( \mathrm { C } ) \mathrm { n } = 3,1 = 1 ( \mathrm { D } ) \mathrm { n } = 3,1 = 2 ( \mathrm { E } ) \mathrm { n } = 4,1 = 0$ Choose the correct answer from the options given below :\\
(1)\\
(B) $>$\\
$( \mathrm { A } ) >$\\
(C) $>$\\
$( \mathrm { E } ) > ( \mathrm { D } )$\\
(2) (E) $< ($ C $) <$\\
(D) $< ($ A $) < ($ B )\\
(3)\\
$( \mathrm { E } ) > ( \mathrm { C } ) > ( \mathrm { A } ) > ( \mathrm { D } ) > ( B )$\\
(4) (C) $<$ (E) $<$\\
(D) $<$ (A) $<$ (B)