jee-main 2020 Q65

jee-main · India · session2_05sep_shift1 Differentiating Transcendental Functions Determine parameters from function or curve conditions

If the function $f ( x ) = \left\{ \begin{array} { c c } k _ { 1 } ( x - \pi ) ^ { 2 } - 1 , & x \leq \pi \\ k _ { 2 } \cos x , & x > \pi \end{array} \right.$ is twice differentiable, then the ordered pair $\left( k _ { 1 } , k _ { 2 } \right)$ is equal to:
(1) $\left( \frac { 1 } { 2 } , 1 \right)$
(2) $( 1,0 )$
(3) $\left( \frac { 1 } { 2 } , - 1 \right)$
(4) $( 1,1 )$

If the function $f ( x ) = \left\{ \begin{array} { c c } k _ { 1 } ( x - \pi ) ^ { 2 } - 1 , & x \leq \pi \\ k _ { 2 } \cos x , & x > \pi \end{array} \right.$ is twice differentiable, then the ordered pair $\left( k _ { 1 } , k _ { 2 } \right)$ is equal to:\\
(1) $\left( \frac { 1 } { 2 } , 1 \right)$\\
(2) $( 1,0 )$\\
(3) $\left( \frac { 1 } { 2 } , - 1 \right)$\\
(4) $( 1,1 )$

Paper Questions

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