jee-main 2020 Q59

jee-main · India · session2_05sep_shift1 Proof Direct Proof of a Stated Identity or Equality

The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to:
(1) $( \sim x \wedge y ) \vee ( \sim x \wedge \sim y )$
(2) $( x \wedge y ) \vee ( \sim x \wedge \sim y )$
(3) $( x \wedge \sim y ) \vee ( \sim x \wedge y )$
(4) $( x \wedge y ) \wedge ( \sim x \vee \sim y )$

The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to:\\
(1) $( \sim x \wedge y ) \vee ( \sim x \wedge \sim y )$\\
(2) $( x \wedge y ) \vee ( \sim x \wedge \sim y )$\\
(3) $( x \wedge \sim y ) \vee ( \sim x \wedge y )$\\
(4) $( x \wedge y ) \wedge ( \sim x \vee \sim y )$

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