jee-main 2025 Q7

jee-main · India · session1_22jan_shift2 Areas Between Curves Compute Area Directly (Numerical Answer)
The area of the region enclosed by the curves $y = x ^ { 2 } - 4 x + 4$ and $y ^ { 2 } = 16 - 8 x$ is :
(1) $\frac { 8 } { 3 }$
(2) $\frac { 4 } { 3 }$
(3) 8
(4) 5
The area of the region enclosed by the curves $y = x ^ { 2 } - 4 x + 4$ and $y ^ { 2 } = 16 - 8 x$ is :\\
(1) $\frac { 8 } { 3 }$\\
(2) $\frac { 4 } { 3 }$\\
(3) 8\\
(4) 5