An isosceles triangle with base 6 cms. and base angles $30^\circ$ each is inscribed in a circle. A second circle touches the first circle and also touches the base of the triangle at its midpoint. If the second circle is situated outside the triangle, then its radius (in cms.) is\\
(A) $3\sqrt{3}/2$\\
(B) $\sqrt{3}/2$\\
(C) $\sqrt{3}$\\
(D) $4/\sqrt{3}$