jee-main 2017 Q71

jee-main · India · 09apr Tangents, normals and gradients Normal or perpendicular line problems

The normal to the curve $y ( x - 2 ) ( x - 3 ) = x + 6$ at the point where the curve intersects the $y$-axis passes through the point:
(1) $\left( \frac { 1 } { 2 } , - \frac { 1 } { 3 } \right)$
(2) $\left( \frac { 1 } { 2 } , \frac { 1 } { 3 } \right)$
(3) $\left( - \frac { 1 } { 2 } , - \frac { 1 } { 2 } \right)$
(4) $\left( \frac { 1 } { 2 } , \frac { 1 } { 2 } \right)$

The normal to the curve $y ( x - 2 ) ( x - 3 ) = x + 6$ at the point where the curve intersects the $y$-axis passes through the point:\\
(1) $\left( \frac { 1 } { 2 } , - \frac { 1 } { 3 } \right)$\\
(2) $\left( \frac { 1 } { 2 } , \frac { 1 } { 3 } \right)$\\
(3) $\left( - \frac { 1 } { 2 } , - \frac { 1 } { 2 } \right)$\\
(4) $\left( \frac { 1 } { 2 } , \frac { 1 } { 2 } \right)$

Paper Questions

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