The distance of the point $(1, 3, -7)$ from the plane passing through the point $(1, -1, -1)$, having normal perpendicular to both the lines
$$\frac { x - 1 } { 1 } = \frac { y + 2 } { - 2 } = \frac { z - 4 } { 3 } \quad \text{and} \quad \frac { x - 2 } { 2 } = \frac { y + 1 } { - 1 } = \frac { z + 7 } { - 1 }$$
is:\\
(1) $\frac { 10 } { \sqrt { 74 } }$\\
(2) $\frac { 20 } { \sqrt { 74 } }$\\
(3) $\frac { 5 } { \sqrt { 83 } }$\\
(4) $\frac { 10 } { \sqrt { 83 } }$