jee-main 2014 Q83

jee-main · India · 06apr Integration by Substitution Substitution to Transform Integral Form (Show Transformed Expression)

The integral $\int \left( 1 + x - \frac { 1 } { x } \right) e ^ { x + \frac { 1 } { x } } d x$, is equal to
(1) $( x + 1 ) e ^ { x + \frac { 1 } { x } } + c$
(2) $- x e ^ { x + \frac { 1 } { x } } + c$
(3) $( x - 1 ) e ^ { x + \frac { 1 } { x } } + c$
(4) $x e ^ { x + \frac { 1 } { x } } + c$

The integral $\int \left( 1 + x - \frac { 1 } { x } \right) e ^ { x + \frac { 1 } { x } } d x$, is equal to\\
(1) $( x + 1 ) e ^ { x + \frac { 1 } { x } } + c$\\
(2) $- x e ^ { x + \frac { 1 } { x } } + c$\\
(3) $( x - 1 ) e ^ { x + \frac { 1 } { x } } + c$\\
(4) $x e ^ { x + \frac { 1 } { x } } + c$

Paper Questions

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