\textbf{118.} If $f$ is differentiable at $x = 4$ and $\displaystyle\lim_{x \to 4} \frac{f(x) + 5}{x - 4} = \frac{-3}{2}$, then $\dfrac{f(2x)}{x}$ at $x = 2$ equals:
\medskip
(1) $-\dfrac{1}{4}$ \hfill (2) $-\dfrac{1}{2}$ \hfill (3) $\dfrac{1}{4}$ \hfill (4) $\dfrac{1}{2}$
\medskip