227. 1 mole of ozone gas is placed in a 1-liter flask and allowed to reach equilibrium: $\mathrm{3O_2(g) \rightleftharpoons 2O_3(g)}$, grams. If at the moment of equilibrium, the molar concentration of ozone gas is $\dfrac{1}{6}$ of the molar concentration of oxygen gas, what is the equilibrium constant of this reaction? (1) $fY/Y\ \mathrm{L.mol^{-1}}$ (2) $fY/Y\ \mathrm{mol.L^{-1}}$ (3) $\circ/\mathit{6}\ \mathrm{L.mol^{-1}}$ (4) $\circ/\mathit{6}\ \mathrm{mol.L^{-1}}$
\textbf{227.} 1 mole of ozone gas is placed in a 1-liter flask and allowed to reach equilibrium: $\mathrm{3O_2(g) \rightleftharpoons 2O_3(g)}$, grams. If at the moment of equilibrium, the molar concentration of ozone gas is $\dfrac{1}{6}$ of the molar concentration of oxygen gas, what is the equilibrium constant of this reaction?
(1) $fY/Y\ \mathrm{L.mol^{-1}}$ \quad (2) $fY/Y\ \mathrm{mol.L^{-1}}$ \quad (3) $\circ/\mathit{6}\ \mathrm{L.mol^{-1}}$ \quad (4) $\circ/\mathit{6}\ \mathrm{mol.L^{-1}}$