\textbf{177.} Inside a uniform electric field, a point charge $q = +2\,\mu\text{C}$ moves from point A to point B. The electric force does work on this charge. If the work done during this transfer equals $J = +5\times10^{-5}\,\text{J}$, the change in electric potential energy of the charge is how many joules, and $V_B - V_A$ equals how many volts?
\begin{itemize}
\item[(1)] $-\Delta\times10^{-5}$ and $-25$
\item[(2)] $-\Delta\times10^{-5}$ and $+25$
\item[(3)] $+\Delta\times10^{-5}$ and $-25$
\item[(4)] $+\Delta\times10^{-5}$ and $+25$
\end{itemize}
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