\textbf{189.} The equation of position of a simple harmonic oscillator in SI units is $x = \circ + \dfrac{\pi^2}{\mathbf{f}}\,\mathbf{a}$ at $t = \dfrac{1}{\mathbf{r}}\,\text{s}$. At this moment, the kinetic energy of the oscillator is how many times its total mechanical energy? (The oscillator passes through $x = \circ$ at $t = \circ$.)
$$\frac{1}{\mathbf{f}} \quad (4) \qquad \frac{1}{\mathbf{r}} \quad (3) \qquad \frac{\mathbf{r}}{\mathbf{f}} \quad (2) \qquad 1 \quad (1)$$