| (2) $2\sqrt{2}$ | (1) $\sqrt{6}$ |
| (4) $3\sqrt{2}$ | (3) $2\sqrt{3}$ |
\textbf{134.} The distance between the two lines $\dfrac{x-1}{2} = \dfrac{y+2}{1} = \dfrac{z}{-1}$ and $\left(x = 2y+1,\ z = -y+2\right)$ is:
\begin{tabular}{ll}
(2) $2\sqrt{2}$ & (1) $\sqrt{6}$ \\
(4) $3\sqrt{2}$ & (3) $2\sqrt{3}$
\end{tabular}
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