\textbf{218-} $\Delta H$ of dissolving calcium chloride $(M = 111\ \text{g.mol}^{-1})$ in water is $-35\ \text{kJ.mol}^{-1}$. To dissolve 250 grams of it in water from $25^\circ\text{C}$ to $45^\circ\text{C}$, how many grams of water must be used? $(c_{\text{water}} = 4/2\ \text{J.g}^{-1}.^\circ\text{C}^{-1}$, heat absorbed by the calcium chloride solution is neglected.)
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(1) $44/4$ \hfill (2) $66/6$ \hfill (3) $83/75$ \hfill (4) $149/85$
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