\textbf{222.} The dissolution of hydrogen sulfide gas at $25^\circ\mathrm{C}$: $0.34\,\mathrm{g}$ per $100\,\mathrm{g}$ of water at $(P = 1\,\mathrm{atm})$ is $500\,\mathrm{g}$ of water. Under these conditions, how many liters of solution contain $3.04\,\mathrm{g}$ of iron(II) sulfate dissolved?
$$(\mathrm{Fe} = 56,\ \mathrm{S} = 32,\ \mathrm{O} = 16,\ \mathrm{H} = 1\ :\ \mathrm{g.mol^{-1}})$$
\begin{center}
(1) 2 \qquad (2) 2.5 \qquad (3) 3 \qquad (4) 3.5
\end{center}