| (2) $AM < AB$ | (1) $AM < BC$ |
| (4) $AD < AM$ | (3) $AD < AB$ |
\textbf{128.} In triangle $ABC$, $AM$ is the median and $AD$ is the interior angle bisector. Which of the following is always true?
\begin{tabular}{ll}
(2) $AM < AB$ & (1) $AM < BC$ \\
(4) $AD < AM$ & (3) $AD < AB$
\end{tabular}