jee-main 2026 Q10

jee-main · India · session1_28jan_shift1 Not Maths
Position of a particle is given by $\mathbf { x } = \mathbf { A } \boldsymbol { \operatorname { s i n } } ( \omega \mathbf { t } )$ potential energy is minimum at $t = \frac { T } { 2 \beta }$, where $T$ is time period. Find minimum value of positive $\boldsymbol { \beta }$. (A) 1 (B) 2 (C) 3 (D) 4
Position of a particle is given by $\mathbf { x } = \mathbf { A } \boldsymbol { \operatorname { s i n } } ( \omega \mathbf { t } )$ potential energy is minimum at $t = \frac { T } { 2 \beta }$, where $T$ is time period. Find minimum value of positive $\boldsymbol { \beta }$.
(A) 1
(B) 2
(C) 3
(D) 4