The statement $( p \wedge ( \sim q ) ) \vee ( ( \sim p ) \wedge q ) \vee ( ( \sim p ) \wedge ( \sim q ) )$ is equivalent to\\ (1) $\sim p \vee q$\\ (2) $\sim p \vee \sim q$\\ (3) $p \vee \sim q$\\ (4) $p \vee q$