LFM Stats And Pure

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Q63. If the set $R = \{ ( a , b ) : a + 5 b = 42 , a , b \in \mathbb { N } \}$ has $m$ elements and $\sum _ { n = 1 } ^ { m } \left( 1 - i ^ { n ! } \right) = x + i y$, where $i = \sqrt { - 1 }$ , then the value of $m + x + y$ is
(1) 12
(2) 4
(3) 8
(4) 5
Q63. The coefficient of $x ^ { 70 }$ in $x ^ { 2 } ( 1 + x ) ^ { 98 } + x ^ { 3 } ( 1 + x ) ^ { 97 } + x ^ { 4 } ( 1 + x ) ^ { 96 } + \ldots + x ^ { 54 } ( 1 + x ) ^ { 46 }$ is ${ } ^ { 99 } \mathrm { C } _ { \mathrm { p } } - { } ^ { 46 } \mathrm { C } _ { \mathrm { q } }$. Then a possible value of $p + q$ is :
(1) 55
(2) 83
(3) 61
(4) 68
Q64. If the coefficients of $x ^ { 4 } , x ^ { 5 }$ and $x ^ { 6 }$ in the expansion of $( 1 + x ) ^ { n }$ are in the arithmetic progression, then the maximum value of $n$ is:
(1) 7
(2) 21
(3) 28
(4) 14
Q64. If the constant term in the expansion of $\left( \frac { \sqrt [ 5 ] { 3 } } { x } + \frac { 2 x } { \sqrt [ 3 ] { 5 } } \right) ^ { 12 } , x \neq 0$, is $\alpha \times 2 ^ { 8 } \times \sqrt [ 5 ] { 3 }$, then $25 \alpha$ is equal to :
(1) 724
(2) 742
(3) 639
(4) 693
Q64. If the term independent of $x$ in the expansion of $\left( \sqrt { \mathrm { a } } x ^ { 2 } + \frac { 1 } { 2 x ^ { 3 } } \right) ^ { 10 }$ is 105 , then $\mathrm { a } ^ { 2 }$ is equal to :
(1) 2
(2) 4
(3) 6
(4) 9
Q65. The sum of all rational terms in the expansion of $\left( 2 ^ { \frac { 1 } { 5 } } + 5 ^ { \frac { 1 } { 3 } } \right) ^ { 15 }$ is equal to :
(1) 3133
(2) 931
(3) 6131
(4) 633
Q81. Let $a = 1 + \frac { { } ^ { 2 } \mathrm { C } _ { 2 } } { 3 ! } + \frac { { } ^ { 3 } \mathrm { C } _ { 2 } } { 4 ! } + \frac { { } ^ { 4 } \mathrm { C } _ { 2 } } { 5 ! } + \ldots , \mathrm { b } = 1 + \frac { { } ^ { 1 } \mathrm { C } _ { 0 } + { } ^ { 1 } \mathrm { C } _ { 1 } } { 1 ! } + \frac { { } ^ { 2 } \mathrm { C } _ { 0 } + { } ^ { 2 } \mathrm { C } _ { 1 } + { } ^ { 2 } \mathrm { C } _ { 2 } } { 2 ! } + \frac { { } ^ { 3 } \mathrm { C } _ { 0 } + { } ^ { 3 } \mathrm { C } _ { 1 } + { } ^ { 3 } \mathrm { C } _ { 2 } + { } ^ { 3 } \mathrm { C } _ { 3 } } { 3 ! } + \ldots$ Then $\frac { 2 b } { a ^ { 2 } }$ is equal to
Q82. If $\mathrm { S } ( x ) = ( 1 + x ) + 2 ( 1 + x ) ^ { 2 } + 3 ( 1 + x ) ^ { 3 } + \cdots + 60 ( 1 + x ) ^ { 60 } , x \neq 0$, and $( 60 ) ^ { 2 } \mathrm {~S} ( 60 ) = \mathrm { a } ( \mathrm { b } ) ^ { \mathrm { b } } + \mathrm { b }$, where $a , b \in N$, then $( a + b )$ equal to $\_\_\_\_$
Q83. If the second, third and fourth terms in the expansion of $( x + y ) ^ { n }$ are 135,30 and $\frac { 10 } { 3 }$, respectively, then $6 \left( n ^ { 3 } + x ^ { 2 } + y \right)$ is equal to $\_\_\_\_$
Q83. Let $\alpha = \sum _ { r = 0 } ^ { n } \left( 4 r ^ { 2 } + 2 r + 1 \right) ^ { n } C _ { r }$ and $\beta = \left( \sum _ { r = 0 } ^ { n } \frac { { } ^ { n } C _ { r } } { r + 1 } \right) + \frac { 1 } { n + 1 }$. If $140 < \frac { 2 \alpha } { \beta } < 281$, then the value of $n$ is $\_\_\_\_$
The sum of coefficients of $\mathbf { x } ^ { \mathbf { 4 9 9 } }$ and $\mathbf { x } ^ { \mathbf { 5 0 0 } }$ in the binomial expansion of $( 1 + x ) ^ { 1000 } + ( 1 + x ) ^ { 999 } ( x ) + x ^ { 2 } ( 1 + x ) ^ { 998 } + \cdots + x ^ { 1000 }$ is (A) ${ } ^ { 1002 } \mathrm { C } _ { 501 }$ lool terms (B) ${ } ^ { 1001 } \mathrm { C } _ { 501 }$ (C) ${ } ^ { 1001 } \mathrm { C } _ { 500 } \quad \gamma = \frac { x } { 1 + x }$ (D) ${ } ^ { 1002 } \mathrm { C } _ { 500 }$
The value of sum $\mathrm { S } = \stackrel { x } { \left( \frac { 1 } { 3 } + \frac { 4 } { 7 } \right) } + \left( \left( \frac { 1 } { 3 } \right) ^ { 2 } + \left( \frac { 4 } { 7 } \right) ^ { 2 } + \left( \frac { 1 } { 3 } \right) \left( \frac { 4 } { 7 } \right) \right) + \left( \left( \frac { 1 } { 3 } \right) ^ { 3 } + \left( \frac { 1 } { 3 } \right) ^ { 2 } \left( \frac { 4 } { 7 } \right) + \left( \frac { 1 } { 3 } \right) \left( \frac { 4 } { 7 } \right) ^ { 2 } + \left( \frac { 4 } { 7 } \right) ^ { 3 } \right) + \ldots$, then S is equal to $( x + y ) + \left( x ^ { 2 } + y ^ { 2 } + x y \right)$
(A) $\frac { 5 } { 2 }$
(B) $\frac { 3 } { 2 }$
(C) $\frac { 1 } { 2 }$
(D) 2
Let $\mathrm { P } ( \mathrm { n } ) = { } ^ { \mathrm { n } } \mathrm { C } _ { 0 } - \frac { { } ^ { \mathrm { n } } } { \mathrm { R } _ { 1 } } + { } ^ { \mathrm { n } } \mathrm { C } _ { 2 } \frac { { } ^ { \mathrm { n } } = { } ^ { \mathrm { n } } \mathrm { C } _ { 3 } } { \mathrm { y } } \ldots \frac { ( - 1 ) ^ { \mathrm { n } } { } ^ { \mathrm { n } } \mathrm { C } _ { \mathrm { n } } } { \mathrm { n } + 1 }$. Find $\sum _ { \mathrm { n } = 1 } ^ { 25 } \frac { 1 } { \mathrm { P } ( 2 \mathrm { n } ) }$
In the expansion of $\left( \left( 1 + x ^ { 2 } \right) ^ { 2 } ( 1 + x ) ^ { n } \right.$, coefficients of $x , x ^ { 2 }$ and $x ^ { 3 }$ are in A.P, then find sum of all possible values of $n \in N$.
The coefficient of $\mathrm { x } ^ { 48 }$ in
$1 \cdot ( 1 + \mathrm { x } ) + 2 \cdot ( 1 + \mathrm { x } ) ^ { 2 } + 3 \cdot ( 1 + \mathrm { x } ) ^ { 3 } + \ldots + 100 \cdot ( 1 + \mathrm { x } ) ^ { 100 }$ is
(A) $\left( { } ^ { { } ^ { 101 } } \mathrm { C } _ { 46 } \right) - 100$
(B) $\mathbf { 1 0 0 } \left( { } ^ { \mathbf { 1 0 1 } } \mathbf { C } _ { \mathbf { 4 6 } } \right) - { } ^ { \mathbf { 1 0 1 } } \mathbf { C } _ { \mathbf { 4 7 } }$
(C) $\mathbf { 1 0 0 } \left( { } ^ { { } ^ { 101 } } C _ { 49 } \right) - { } ^ { 101 } C _ { 50 }$
(D) ${ } ^ { { } ^ { 101 } } \mathrm { C } _ { 47 } - { } ^ { 101 } \mathrm { C } _ { 46 }$
The value of $\frac { { } ^ { 100 } C _ { 50 } } { 51 } + \frac { { } ^ { 100 } C _ { 51 } } { 52 } + \ldots \ldots \frac { { } ^ { 100 } C _ { 100 } } { 101 }$ is $\sum _ { \gamma = 50 } ^ { 100 } \frac { { } ^ { 100 } C _ { \gamma } } { \gamma + 1 }$\ (A) $\frac { 2 ^ { 100 } } { 100 }$\ (B) $\frac { 2 ^ { 101 } } { 101 }$\ (C) $\frac { 2 ^ { 100 } } { 101 }$\ (D) $\frac { 2 ^ { 101 } } { 100 }$
Consider a polynomial in $x$ and $y$
$$P = ( 3 x + 4 y + 1 ) ^ { 5 } .$$
Let us denote the coefficient of $x ^ { n } y$ in the expansion of $P$ by $a _ { n }$, where $n$ is an integer. Note that $x ^ { 0 } = y ^ { 0 } = 1$.
(1) Let us find the value of the coefficient $a _ { 1 }$. First, we note that
$$P = \{ ( 3 x + 1 ) + 4 y \} ^ { 5 }$$
and use the binomial theorem to expand $P$. Then $x y$ appears when we expand the term AB $( 3 x + 1 ) ^ { \text {C} } y$. Further, the coefficient for $x$ in the expansion of $( 3 x + 1 ) ^ { \text {C} }$ is DE. It follows that
$$a _ { 1 } = \mathbf { F G H } .$$
(2) The number of values which $n$ can take is $\square$ in all. Also, the value of $a _ { n }$ is maximized at $n =$ $\square$ J .
2. For ALL APPLICANTS.
For $k$ a positive integer, we define the polynomial $p _ { k } ( x )$ as
$$p _ { k } ( x ) = ( 1 + x ) \left( 1 + x ^ { 2 } \right) \left( 1 + x ^ { 3 } \right) \times \cdots \times \left( 1 + x ^ { k } \right) = a _ { 0 } + a _ { 1 } x + \cdots + a _ { N } x ^ { N } ,$$
denoting the coefficients of $p _ { k } ( x )$ as $a _ { 0 } , \ldots , a _ { N }$.
(i) Write down the degree $N$ of $p _ { k } ( x )$ in terms of $k$.
(ii) By setting $x = 1$, or otherwise, explain why
$$a _ { \max } \geqslant \frac { 2 ^ { k } } { N + 1 }$$
where $a _ { \text {max } }$ denotes the largest of the coefficients $a _ { 0 } , \ldots , a _ { N }$.
(iii) Fix $i \geqslant 0$. Explain why the value of $a _ { i }$ eventually becomes constant as $k$ increases.
A student correctly calculates for $k = 6$ that $p _ { 6 } ( x )$ equals
$$\begin{aligned} & 1 + x + x ^ { 2 } + 2 x ^ { 3 } + 2 x ^ { 4 } + 3 x ^ { 5 } + 4 x ^ { 6 } + 4 x ^ { 7 } + 4 x ^ { 8 } + 5 x ^ { 9 } + 5 x ^ { 10 } + 5 x ^ { 11 } \\ & + 5 x ^ { 12 } + 4 x ^ { 13 } + 4 x ^ { 14 } + 4 x ^ { 15 } + 3 x ^ { 16 } + 2 x ^ { 17 } + 2 x ^ { 18 } + x ^ { 19 } + x ^ { 20 } + x ^ { 21 } \end{aligned}$$
(iv) On the basis of this calculation, the student guesses that
$$a _ { i } = a _ { N - i } \quad \text { for } \quad 0 \leqslant i \leqslant N$$
By substituting $x ^ { - 1 }$ for $x$, or otherwise, show that the student's guess is correct for all positive integers $k$.
(v) On the basis of the same calculation, the student guesses that all whole numbers in the range $1,2 , \ldots , a _ { \text {max } }$ appear amongst the coefficients $a _ { 0 } , \ldots , a _ { N }$, for all positive integers $k$.
Use part (ii) to show that in this case the student's guess is wrong. Justify your answer.
If you require additional space please use the pages at the end of the booklet
Find the coefficients of $( a + b x ) \cdot ( c + d x )$ in terms of $a , b , c , d$, and explain why $f ( x ) \cdot g ( x ) = g ( x ) \cdot f ( x )$ for all linear polynomials $f ( x )$ and $g ( x )$.
Let $N$ be a whole number with $N > 1$. Find $$( 1 + x ) \cdot ( 1 + 2 x ) \cdot ( 1 + 3 x ) \cdot ( 1 + 4 x ) \cdot \ldots \cdot ( 1 + 2 N x )$$
20. The coefficient of $x ^ { 2 }$ in the expansion of $\left( 4 - x ^ { 2 } \right) \left[ \left( 1 + 2 x + 3 x ^ { 2 } \right) ^ { 6 } - \left( 1 + 4 x ^ { 3 } \right) ^ { 5 } \right]$ is
A 28
B 72
C 78
D 192
E 240
F 310
G 312
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It is given that the expansion of $( a x + b ) ^ { 3 }$ is $8 x ^ { 3 } - p x ^ { 2 } + 18 x - 3 \sqrt { 3 }$, where $a , b$ and $p$ are real constants.
What is the value of $p$ ?
A $- 12 \sqrt { 3 }$ B $- 6 \sqrt { 3 }$ C $- 4 \sqrt { 3 }$ D $- \sqrt { 3 }$ E $\sqrt { 3 }$ F $4 \sqrt { 3 }$ G $6 \sqrt { 3 }$ H $12 \sqrt { 3 }$
The coefficient of $x ^ { 3 }$ in the expansion of $\left( 1 + 2 x + 3 x ^ { 2 } \right) ^ { 6 }$ is equal to twice the coefficient of $x ^ { 4 }$ in the expansion of $\left( 1 - a x ^ { 2 } \right) ^ { 5 }$.
Find all possible values of the constant $a$.
A $\pm 2 \sqrt { 2 }$ B $\pm \sqrt { 17 }$ C $\pm \sqrt { 34 }$ D $\pm 2 \sqrt { 17 }$ E There are no possible values of $a$.
In the expansion of $( a + b x ) ^ { 5 }$ the coefficient of $x ^ { 4 }$ is 8 times the coefficient of $x ^ { 2 }$.
Given that $a$ and $b$ are non-zero positive integers, what is the smallest possible value of $a + b$ ?
A 3
B 4
C 5
D 9
E 13
F 17
Find the value of the constant term in the expansion of
$$\left( x ^ { 6 } - \frac { 1 } { x ^ { 2 } } \right) ^ { 12 }$$