In this question, the space $E$ has dimension $n \geq 2$. For every pair $(\alpha , \beta)$ of non-zero vectors of $E$, let $\theta _ { \alpha , \beta }$ be the geometric angle between $\alpha$ and $\beta$, that is, the unique element of $[ 0 , \pi ]$ given by: $\| \alpha \| . \| \beta \| \cos \theta _ { \alpha , \beta } = \langle \alpha , \beta \rangle$.
Let $\mathcal { R }$ be a root system of $E$ and let $\alpha , \beta$ be two non-collinear elements of $\mathcal { R }$.
a) Show, using property 4, that: $2 \frac { \| \alpha \| } { \| \beta \| } \left| \cos \theta _ { \alpha , \beta } \right| .2 \frac { \| \beta \| } { \| \alpha \| } \left| \cos \theta _ { \alpha , \beta } \right| \leq 3$.
b) Assume $\| \alpha \| \leq \| \beta \|$. Show that the pair $(\alpha , \beta)$ is found in one of the configurations listed in the table below (each row corresponding to a configuration):
| $\theta _ { \alpha , \beta }$ | $\cos \theta _ { \alpha , \beta }$ | $\| \beta \| / \| \alpha \|$ |
| $\pi / 2$ | 0 | $\geq 1$ |
| $\pi / 3$ | $1 / 2$ | 1 |
| $2 \pi / 3$ | $- 1 / 2$ | 1 |
| $\pi / 4$ | $\sqrt { 2 } / 2$ | $\sqrt { 2 }$ |
| $3 \pi / 4$ | $- \sqrt { 2 } / 2$ | $\sqrt { 2 }$ |
| $\pi / 6$ | $\sqrt { 3 } / 2$ | $\sqrt { 3 }$ |
| $5 \pi / 6$ | $- \sqrt { 3 } / 2$ | $\sqrt { 3 }$ |